Find Second highest Number in JAVA.(n number take from user)

This Logic so efficient,when second highest number is input,that only assign a number. 

CODING:

import java.util.Scanner;
class Hightest{
 public static void main(String args[])
  {
    Scanner n=new Scanner(System.in);
    int temp,fi_hi=0,se_hi=0;
    System.out.print("How Many Enter number...");
    for(int i=n.nextInt();i>0;i--){
     System.out.print("Enter Number : ");
     temp=n.nextInt();
       if(fi_hi>temp && temp>se_hi){
        se_hi=temp;
       }
       else if(temp>fi_hi){
        se_hi=fi_hi;
        fi_hi=temp;
       }   
    }
     System.out.println("Second Hightest Number :" + ((se_hi==0) ? se_hi=fi_hi : se_hi));
  }
}